Day 2: Cube Conundrum
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FAQ
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Found a C per-char solution, that is, no lines, splitting, lookahead, etc. It wasn’t even necessary to keep match lengths for the color names because they all have unique characters, e.g. ‘b’ only occurs in “blue” so then you can attribute the count to that color.
int main() { int p1=0,p2=0, id=1,num=0, r=0,g=0,b=0, c; while ((c = getchar()) != EOF) if (c==',' || c==';' || c==':') num = 0; else if (c>='0' && c<='9') num = num*10 + c-'0'; else if (c=='d') r = MAX(r, num); else if (c=='g') g = MAX(g, num); else if (c=='b') b = MAX(b, num); else if (c=='\n') { p1 += (r<=12 && g<=13 && b<=14) * id; p2 += r*g*b; r=g=b=0; id++; } printf("%d %d\n", p1, p2); return 0; }
Golfed:
c,p,P,i,n,r,g,b;main(){while(~ (c=getchar()))c==44|c==58|59== c?n=0:c>47&c<58?n=n*10+c-48:98 ==c?b=b>n?b:n:c=='d'?r=r>n?r:n :c=='g'?g=g>n?g:n:10==c?p+=++i *(r<13&g<14&b<15),P+=r*g*b,r=g =b=0:0;printf("%d %d\n",p,P);}
Rust
Pretty straightforward this time, the bulk of the work was clearly in parsing the input.
Not too tricky today. Part 2 wasn’t as big of a curveball as yesterday thankfully. I don’t think it’s the cleanest code I’ve ever written, but hey - the whole point of this is to get better at Rust, so I’ll definitely be learning as I go, and coming back at the end to clean a lot of these up. I think for this one I’d like to look into a parsing crate like nom to clean up all the spliting and unwrapping in the two from() methods.
https://github.com/capitalpb/advent_of_code_2023/blob/main/src/solvers/day02.rs
#[derive(Debug)] struct Hand { blue: usize, green: usize, red: usize, } impl Hand { fn from(input: &str) -> Hand { let mut hand = Hand { blue: 0, green: 0, red: 0, }; for color in input.split(", ") { let color = color.split_once(' ').unwrap(); match color.1 { "blue" => hand.blue = color.0.parse::().unwrap(), "green" => hand.green = color.0.parse::().unwrap(), "red" => hand.red = color.0.parse::().unwrap(), _ => unreachable!("malformed input"), } } hand } } #[derive(Debug)] struct Game { id: usize, hands: Vec, } impl Game { fn from(input: &str) -> Game { let (id, hands) = input.split_once(": ").unwrap(); let id = id.split_once(" ").unwrap().1.parse::().unwrap(); let hands = hands.split("; ").map(Hand::from).collect(); Game { id, hands } } } pub struct Day02; impl Solver for Day02 { fn star_one(&self, input: &str) -> String { input .lines() .map(Game::from) .filter(|game| { game.hands .iter() .all(|hand| hand.blue <= 14 && hand.green <= 13 && hand.red <= 12) }) .map(|game| game.id) .sum::() .to_string() } fn star_two(&self, input: &str) -> String { input .lines() .map(Game::from) .map(|game| { let max_blue = game.hands.iter().map(|hand| hand.blue).max().unwrap(); let max_green = game.hands.iter().map(|hand| hand.green).max().unwrap(); let max_red = game.hands.iter().map(|hand| hand.red).max().unwrap(); max_blue * max_green * max_red }) .sum::() .to_string() } }
Factor on github (with comments and imports):
: known-color ( color-phrases regexp -- n ) all-matching-subseqs [ 0 ] [ [ split-words first string>number ] map-supremum ] if-empty ; : line>known-rgb ( str -- game-id known-rgb ) ": " split1 [ split-words last string>number ] dip R/ \d+ red/ R/ \d+ green/ R/ \d+ blue/ [ known-color ] tri-curry@ tri 3array ; : possible? ( known-rgb test-rgb -- ? ) v<= [ ] all? ; : part1 ( -- ) "vocab:aoc-2023/day02/input.txt" utf8 file-lines [ line>known-rgb 2array ] [ last { 12 13 14 } possible? ] map-filter [ first ] map-sum . ; : part2 ( -- ) "vocab:aoc-2023/day02/input.txt" utf8 file-lines [ line>known-rgb nip product ] map-sum . ;
Ruby
https://github.com/snowe2010/advent-of-code/blob/master/ruby_aoc/2023/day02/day02.rb
Second part was soooo much easier today than yesterday. Helps I solved it exactly how he wanted you to solve it I think.
I’m going to work on some code golf now.
Golfed P2 down to 133 characters:
p g.map{_1.sub!(/.*:/,'') m=Hash.new(0) _1.split(?;){|r|r.split(?,){|a|b,c=a.split m[c]=[m[c],b.to_i].max}} m.values.reduce(&:*)}.sum
That’s a nice golf! Clever use of the hash and nice compact reduce. I got my C both-parts solution down to 210 but it’s not half as nice.
Thanks! Your C solution includes main, whereas I do some stuff to parse the lines before hand. I think it would only be 1 extra character if I wrote it to parse the input manually, but I just care for ease of use with these AoC problems so I don’t like counting that, makes it harder to read for me lol. Your solution is really inventive. I was looking for something like that, but didn’t ever get to your conclusion. I wonder if that would be longer in my solution or shorter 🤔
This was mostly straightforward… basically just parsing input. Here are my condensed solutions in Python
Part 1
Game = dict[str, int] RED_MAX = 12 GREEN_MAX = 13 BLUE_MAX = 14 def read_game(stream=sys.stdin) -> Game: try: game_string, cubes_string = stream.readline().split(':') except ValueError: return {} game: Game = defaultdict(int) game['id'] = int(game_string.split()[-1]) for cubes in cubes_string.split(';'): for cube in cubes.split(','): count, color = cube.split() game[color] = max(game[color], int(count)) return game def read_games(stream=sys.stdin) -> Iterator[Game]: while game := read_game(stream): yield game def is_valid_game(game: Game) -> bool: return all([ game['red'] <= RED_MAX, game['green'] <= GREEN_MAX, game['blue'] <= BLUE_MAX, ]) def main(stream=sys.stdin) -> None: valid_games = filter(is_valid_game, read_games(stream)) sum_of_ids = sum(game['id'] for game in valid_games) print(sum_of_ids)
Part 2
For the second part, the main parsing remainded the same. I just had to change what I did with the games I read.
def power(game: Game) -> int: return game['red'] * game['green'] * game['blue'] def main(stream=sys.stdin) -> None: sum_of_sets = sum(power(game) for game in read_games(stream)) print(sum_of_sets)
I had some time, so here’s a terrible solution in Uiua (Run it here) :
Lim ← [14 13 12] {"Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green" "Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue" "Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red" "Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red" "Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green"} LtoDec ← ∧(+ ×10:) :0 StoDec ← LtoDec▽≥0. ▽≤9. -@0 FilterMax! ← /↥≡(StoDec⊢↙ ¯1)⊔⊏⊚≡(/×^1⊢).⊔ # Build 'map' of draws for each game ∵(□≡(∵(⬚@\s↙2 ⊔) ⇌) ↯¯1_2 ↘ 2⊜□≠@\s . ⊔) # Only need the max for each colour ≡(⊂⊂⊃⊃(FilterMax!(="bl")) (FilterMax!(="gr")) (FilterMax!(="re"))) # part 1 - Compare against limits, and sum game numbers /+▽:+1⇡⧻. ≡(/×≤0-Lim). # part 2 - Multiply the maxes in each game and then sum. /+/×⍉:
C# - a tad bit overkill for this. I was worried that we’d need more statistical analysis in part 2, so I designed my solution around that. I ended up cutting everything back when
Max()
was enough for both parts.https://github.com/warriordog/advent-of-code-2023/tree/main/Solutions/Day02
A solution in Nim language. Pretty straightforward code. Most logic is just parsing input + a bit of functional utils: allIt checks if all items in a list within limits to check if game is possible and
mapIt
collects red, green, blue cubes from each set of game.https://codeberg.org/Archargelod/aoc23-nim/src/branch/master/day_02/solution.nim
import std/[strutils, strformat, sequtils] type AOCSolution[T] = tuple[part1: T, part2: T] type GameSet = object red, green, blue: int Game = object id: int sets: seq[GameSet] const MaxSet = GameSet(red: 12, green: 13, blue: 14) func parseGame(input: string): Game = result.id = input.split({':', ' '})[1].parseInt() let sets = input.split(": ")[1].split("; ").mapIt(it.split(", ")) for gSet in sets: var gs = GameSet() for pair in gSet: let pair = pair.split() cCount = pair[0].parseInt cName = pair[1] case cName: of "red": gs.red = cCount of "green": gs.green = cCount of "blue": gs.blue = cCount result.sets.add gs func isPossible(g: Game): bool = g.sets.allIt( it.red <= MaxSet.red and it.green <= MaxSet.green and it.blue <= MaxSet.blue ) func solve(lines: seq[string]): AOCSolution[int]= for line in lines: let game = line.parseGame() block p1: if game.isPossible(): result.part1 += game.id block p2: let minRed = game.sets.mapIt(it.red).max() minGreen = game.sets.mapIt(it.green).max() minBlue = game.sets.mapIt(it.blue).max() result.part2 += minRed * minGreen * minBlue when isMainModule: let input = readFile("./input.txt").strip() let (part1, part2) = solve(input.splitLines()) echo &"Part 1: The sum of valid game IDs equals {part1}." echo &"Part 2: The sum of the sets' powers equals {part2}."
Another nim person! Have you joined the community? There are dozens of us!
Here’s mine (no code blocks because kbin):
Hi there! Looks like you linked to a Lemmy community using a URL instead of its name, which doesn’t work well for people on different instances. Try fixing it like this: [email protected]
Have you joined the community?
Yep, but it is a bit quiet in there.
Good solution. I like your parsing with scanf. The only reason I didn’t use it myself - is that I found out about std/strscans literally yesterday.
I actually just learned about scanf while writing this. Only ended up using it in the one spot, since split worked well enough for the other bits. I really wanted to be able to use python-style unpacking, but in nim it only works for tuples. At least without writing macros, which I still haven’t been able to wrap my head around.
Late as always, as I’m on UK time and can’t work on these until late evening.
Part 01 and Part 02 in Rust 🦀 :
use std::{ env, fs, io::{self, BufRead, BufReader}, }; #[derive(Debug)] struct Sample { r: u32, g: u32, b: u32, } fn split_cube_set(set: &[&str], colour: &str) -> Option { match set.iter().find(|x| x.ends_with(colour)) { Some(item) => item .trim() .split(' ') .next() .expect("Found item is present") .parse::() .ok(), None => None, } } fn main() -> io::Result<()> { let args: Vec = env::args().collect(); let filename = &args[1]; let file = fs::File::open(filename)?; let reader = BufReader::new(file); let mut valid_game_ids_sum = 0; let mut game_power_sum = 0; let max_r = 12; let max_g = 13; let max_b = 14; for line_result in reader.lines() { let mut valid_game = true; let line = line_result.unwrap(); let line_split: Vec<_> = line.split(':').collect(); let game_id = line_split[0] .split(' ') .collect::>() .last() .expect("item exists") .parse::() .expect("is a number"); let rest = line_split[1]; let cube_sets = rest.split(';'); let samples: Vec = cube_sets .map(|set| { let set_split: Vec<_> = set.split(',').collect(); let r = split_cube_set(&set_split, "red").unwrap_or(0); let g = split_cube_set(&set_split, "green").unwrap_or(0); let b = split_cube_set(&set_split, "blue").unwrap_or(0); Sample { r, g, b } }) .collect(); let mut highest_r = 0; let mut highest_g = 0; let mut highest_b = 0; for sample in &samples { if !(sample.r <= max_r && sample.g <= max_g && sample.b <= max_b) { valid_game = false; } highest_r = u32::max(highest_r, sample.r); highest_g = u32::max(highest_g, sample.g); highest_b = u32::max(highest_b, sample.b); } if valid_game { valid_game_ids_sum += game_id; } game_power_sum += highest_r * highest_g * highest_b; } println!("Sum of game ids: {valid_game_ids_sum}"); println!("Sum of game powers: {game_power_sum}"); Ok(()) }
Spent most of the time running down annoying typos in the tokenizer.
Did mine in Odin. Found this day’s to be super easy, most of the challenge was just parsing.
package day2 import "core:fmt" import "core:strings" import "core:strconv" import "core:unicode" Round :: struct { red: int, green: int, blue: int, } parse_round :: proc(s: string) -> Round { ret: Round rest := s for { nextNumAt := strings.index_proc(rest, unicode.is_digit) if nextNumAt == -1 do break rest = rest[nextNumAt:] numlen: int num, ok := strconv.parse_int(rest, 10, &numlen) rest = rest[numlen+len(" "):] if rest[:3] == "red" { ret.red = num } else if rest[:4] == "blue" { ret.blue = num } else if rest[:5] == "green" { ret.green = num } } return ret } Game :: struct { id: int, rounds: [dynamic]Round, } parse_game :: proc(s: string) -> Game { ret: Game rest := s[len("Game "):] idOk: bool idLen: int ret.id, idOk = strconv.parse_int(rest, 10, &idLen) rest = rest[idLen+len(": "):] for len(rest) > 0 { endOfRound := strings.index_rune(rest, ';') if endOfRound == -1 do endOfRound = len(rest) append(&ret.rounds, parse_round(rest[:endOfRound])) rest = rest[min(endOfRound+1, len(rest)):] } return ret } is_game_possible :: proc(game: Game) -> bool { for round in game.rounds { if round.red > 12 || round.green > 13 || round.blue > 14 { return false } } return true } p1 :: proc(input: []string) { totalIds := 0 for line in input { game := parse_game(line) defer delete(game.rounds) if is_game_possible(game) do totalIds += game.id } fmt.println(totalIds) } p2 :: proc(input: []string) { totalPower := 0 for line in input { game := parse_game(line) defer delete(game.rounds) minRed := 0 minGreen := 0 minBlue := 0 for round in game.rounds { minRed = max(minRed , round.red ) minGreen = max(minGreen, round.green) minBlue = max(minBlue , round.blue ) } totalPower += minRed * minGreen * minBlue } fmt.println(totalPower) }
Getting my head around parsing tricks for python, maybe abusing dicts as a replacement for a types, but appears to be working: https://gist.github.com/purplemonkeymad/983eec7ff0629e8834163b17ec673958
Was pretty simple in Python with a regex to get the game number, and then the count of color. for part 2 instead of returning true/false whether the game is valid, you just max the count per color. No traps like in the first one, that I’ve seen, so it was surprisingly easy
def process_game(line: str): game_id = int(re.findall(r'game (\d+)*', line)[0]) colon_idx = line.index(":") draws = line[colon_idx+1:].split(";") # print(draws) if is_game_valid(draws): # print("Game %d is possible"%game_id) return game_id return 0 def is_game_valid(draws: list): for draw in draws: red = get_nr_of_in_draw(draw, 'red') if red > MAX_RED: return False green = get_nr_of_in_draw(draw, 'green') if green > MAX_GREEN: return False blue = get_nr_of_in_draw(draw, 'blue') if blue > MAX_BLUE: return False return True def get_nr_of_in_draw(draw: str, color: str): if color in draw: nr = re.findall(r'(\d+) '+color, draw) return int(nr[0]) return 0 # f = open("input.txt", "r") f = open("input_real.txt", "r") lines = f.readlines() sum = 0 for line in lines: sum += process_game(line.strip().lower()) print("Answer: %d"%sum)
My (awful) Python solves. Much easier than day 1’s, although I did run into an issue with trimming whitespace characters with my approach (Game 96 wouldn’t flag properly).
Part 1
with open('02A_input.txt', 'r') as file: data = file.readlines() possibleGames=[] for game in data: # Find Game number game = game.removeprefix("Game ") gameNumber = int(game[0:game.find(":")]) # Break Game into rounds (split using semicolons) game=game[game.find(":")+1:] rounds=game.split(";") # For each round, determine the maximum number of Red, Blue, Green items shown at a time rgb=[0,0,0] for round in rounds: combos=round.split(",") for combo in combos: combo=combo.strip() number=int(combo[0:combo.find(" ")]) if combo.endswith("red"): if number>rgb[0]: rgb[0]=number elif combo.endswith("green"): if number>rgb[1]: rgb[1]=number elif combo.endswith("blue"): if number>rgb[2]: rgb[2]=number # If Red>12, Green>13, Blue>14, append Game number to possibleGames if not (rgb[0]>12 or rgb[1]>13 or rgb[2]>14): possibleGames.append(gameNumber) print(sum(possibleGames))
Part 2
with open('02A_input.txt', 'r') as file: data = file.readlines() powers=[] for game in data: # Find Game number game = game.removeprefix("Game ") # Break Game into rounds (split using semicolons) game=game[game.find(":")+1:] rounds=game.split(";") # For each round, determine the maximum number of Red, Blue, Green items shown at a time # Note: This could be faster, since we don't need to worry about actual rounds rgb=[0,0,0] for round in rounds: combos=round.split(",") for combo in combos: combo=combo.strip() number=int(combo[0:combo.find(" ")]) if combo.endswith("red"): if number>rgb[0]: rgb[0]=number elif combo.endswith("green"): if number>rgb[1]: rgb[1]=number elif combo.endswith("blue"): if number>rgb[2]: rgb[2]=number # Multiple R, G, B to find the "power" of the game # Append Power to the list powers.append(rgb[0]*rgb[1]*rgb[2]) print(sum(powers))